Question

NAME THE Y-INTERCEPT y = -(x - 3)2 - 1

Answer 1

$\begin{gathered} y=-(x-3)^2-1 \\ y=-(x-3)(x-3)-1 \\ y=-(x^2-6x^{}+9)-1 \\ y=-(x^2-6x+9)-1 \\ y=-x^2+6x-9-1 \\ y=-x^2+6x-10 \end{gathered}$

Y intercepts when x = 0

$\begin{gathered} y=-(0)^2+6(0)-10 \\ y=-10 \end{gathered}$