Question

There are 3 consecutive integers that have a sum of 156. What is the value of the greatestinteger?

Answer 1

Answer:

53

Explanation:

Let the first integer = n

• The second consecutive integer = n+1

,

• The third consecutive integer = n+2

If the sum of the integers is 156, then:

$n+(n+1)+(n+2)=156$

Solve for n.

$\begin{gathered} n+n+n+1+2=156 \\ 3n+3=156 \\ 3n=156-3 \\ 3n=153 \\ n=\frac{153}{3} \\ n=51 \end{gathered}$

Thus, the value of the greatest consecutive integer will be:

$\begin{gathered} n+2=51+2 \\ =53 \end{gathered}$