So we have to find the equation of a line that passes through (2,4) and has a slope of 1/2 in standard form. First, we should write it in point-slope form because it will be easier to find it. Then we can change it into the standard form. The point-slope form of a line with a slope m that passes through point (a,b) is:
[tex]y-b=m(x-a)[/tex]In this case we are told that the slope is 1/2 and the point is (2,4) so we get:
[tex]y-4=\frac{1}{2}(x-2)[/tex]Now that we have the equation in point-slope form we must convert it into the standard form. This form looks like the following:
[tex]Ax+By=C[/tex]Where A, B and C are numbers. So let's take the equation we found before and distribute the product in the right side:
[tex]\begin{gathered} y-4=\frac{1}{2}(x-2) \\ y-4=\frac{x}{2}-\frac{2}{2} \\ y-4=\frac{x}{2}-1 \end{gathered}[/tex]Now let's add 4 to both sides:
[tex]\begin{gathered} y-4=\frac{x}{2}-1 \\ y-4+4=\frac{x}{2}-1+4 \\ y=\frac{x}{2}+3 \end{gathered}[/tex]We substract x/2 from both sides:
[tex]\begin{gathered} y=\frac{x}{2}+3 \\ y-\frac{x}{2}=\frac{x}{2}+3-\frac{x}{2} \\ -\frac{x}{2}+y=3 \end{gathered}[/tex]And finally we multiply both sides by 2:
[tex]\begin{gathered} 2\cdot(-\frac{x}{2}+y)=2\cdot3 \\ -x+2y=6 \end{gathered}[/tex]Then the answer is option b.