Solution:
Given:
[tex](3,4)\text{ }and\text{ }(2,1)[/tex]The distance between the points is gotten using the formula;
[tex]\begin{gathered} d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} \\ where: \\ x_1=3,y_1=4 \\ x_2=2,y_2=1 \end{gathered}[/tex]Hence,
[tex]\begin{gathered} d=\sqrt{(3-2)^2+(4-1)^2} \\ d=\sqrt{1^2+3^2} \\ d=\sqrt{1+9} \\ d=\sqrt{10}\text{ }units \end{gathered}[/tex]Therefore, the distance between (3,4) and (2,1) is;
[tex]\sqrt{10}\text{ units}[/tex]