Question

Solve the triangle whit the given parts g = 6.9, h = 13.9, | = 16.0G Round to 2 delcmal places.

Answer 1

Solution:

We want to solve the given triangle;

$\begin{gathered} cos\angle G=\frac{h^2+i^2-g^2}{2ih} \\ =0.9029 \\ \angle G=cos^{-1}0.9029=25.46^o \end{gathered}$$\begin{gathered} cos\angle H=\frac{g^2+i^2-h^2}{2gi} \\ =0.5 \\ H=cos^{-1}0.5=60^o \end{gathered}$

Thus;

$\angle I=180-60-25.46=94.54^o$

Thus the full measures of the triangle are;

$\begin{gathered} g=6.9,h=13.9,i=16.0 \\ \angle G=25.46^o,\angle H=60^o,\angle I=94.54^o \end{gathered}$