Respuesta :

First we are going to calculate the side BC using the Pythagorean theorem:

[tex]\begin{gathered} BC=\sqrt[]{10^2+20^2} \\ BC=\sqrt[]{300} \\ BC=10\cdot\sqrt[]{3} \end{gathered}[/tex]

From the graph we can determine that:

[tex]\measuredangle C=90º[/tex]

For the calculation of the angle B we will use the sine of the angle:

[tex]\begin{gathered} sinB=\frac{opposite}{hippotenuse} \\ sinB=\frac{10}{20} \\ \measuredangle B=\sin ^{-1}(0.5) \\ \measuredangle B=30º \end{gathered}[/tex]

To find the angle A, we use the law of internal angles of a triangle, which says that the sum of the internal angles of a triangle gives 180º

[tex]\begin{gathered} \measuredangle A+\measuredangle B+\measuredangle C=180º \\ \measuredangle A=180º-30º-90º \\ \measuredangle A=60º \end{gathered}[/tex]

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