The cost of three pants and four shirts is $68.45. If a pant costs $6.85 morethan a shirt, find the cost of a pant and a shirt. Estimate to the nearest wholenumber.

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Solution:

Let the cost of a pant and a shirt be represented by x and y respectively.

This implies that

[tex]\begin{gathered} cost\text{ of a pant}\Rightarrow\$\text{ x} \\ cost\text{ of a shirt}\Rightarrow\$\text{ y} \end{gathered}[/tex]

Given that the cost of three pants and four shirts is $68.45, this implies that

[tex]3x+4y=68.45\text{ ---- equation 1}[/tex]

If a pant costs $6.85 more than a shirt, this implies that

[tex]x=6.85+y\text{ ---- equation 2}[/tex]

To find the cost of a pant and a shirt,

step 1: Substitute equation 2 into equation 1.

Thus, we have

[tex]\begin{gathered} 3x+4y=68.45 \\ \Rightarrow3\left(6.85+y\right)+4y=68.45 \\ open\text{ parentheses,} \\ 20.55+3y+4y=68.45 \\ collect\text{ like terms,} \\ 7y=47.9 \\ divide\text{ both sides by the coefficient of y, which is 7} \\ \frac{7y}{7}=\frac{47.9}{7} \\ \Rightarrow y=6.842857143 \end{gathered}[/tex]

step 2: Substitute the value of y into equation 2.

Thus, we have

[tex]\begin{gathered} x=6.85+y \\ =6.85+6.842857143 \\ \Rightarrow x=13.69285 \\ \end{gathered}[/tex]

Hence, to the nearest whole number, the respective cost of a pant and a shirt is

[tex]\begin{gathered} x=\$14 \\ y=\$7 \end{gathered}[/tex]

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