Respuesta :

Solution:

Given:

[tex]\begin{gathered} \mu=31 \\ \sigma=6 \\ n=4 \end{gathered}[/tex]

The mean of the sampling distribution of sample means, μx¯, is equal to the population mean, μ.

Hence,

[tex]\mu_{\bar{x}}=\mu[/tex]

Hence,

[tex]\mu_{\bar{x}}=31[/tex]

Therefore, the mean of the sampling distribution of sample means is 31.0

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