What is the solution to the equation below? Round your answer to two decimal places.e0.4x = 0.4A.x = -0.37B.x = -0.91C.x = -2.29D.x = -1.73

Given:
An equation is given as
[tex]e^{0.4x}=0.4[/tex]Find:
we have to solve the given equation.
Explanation:
we will solve the equation as following
[tex]\begin{gathered} e^{0.4x}=0.4 \\ Taking\text{ ln on both sides, we get} \\ ln(e^{0.4x})=ln(0.4) \\ 0.4x\times ln(e)=0.9163 \\ 0.4x\times(1)=0.9163 \\ x=\frac{0.9163}{0.4} \\ x=2.29 \end{gathered}[/tex]Therefore, the solution of the given equation is x = 2.29.