For Emmett
Let:
y1 = Total cost
x = Number of minutes
a = Cost of each minute = 1
b = Cost of place a call = 4
For Cooper:
Let:
y2 = Total cost
x = Number of minutes
c = Cost of each minute = 2
d = Cost of place a call
Therefore:
[tex]\begin{gathered} y1=ax+b \\ y1=x+4 \\ -------- \\ y2=cx+d \\ y2=2x+1 \end{gathered}[/tex]We find the duration and the cost of this situation solving the following equation:
[tex]\begin{gathered} y1=y2 \\ x+4=2x+1 \\ _{\text{ }}solve_{\text{ }}for_{\text{ }}x_{}\colon \\ 2x-x=4-1 \\ x=3 \end{gathered}[/tex]Answer:
The cost is $7 and the duration is 3 minutes.