Question

Andre stacks one block of each size. Will that stack be more than 1 foot tall? Explain or show your reasoning

Answer 1

If Andre stakcs one block of each size, the the total height will be

$\frac{1}{3}+\frac{1}{2}+\frac{1}{6}$

Making the sum we have:

$\begin{gathered} \frac{1}{3}+\frac{1}{2}+\frac{1}{6}=\frac{2+3}{6}+\frac{1}{6} \\ =\frac{5}{6}+\frac{1}{6} \\ =\frac{6}{6} \\ =1 \end{gathered}$

The total height will be 1 foot tall, therefore the stack won't be more than 1 foot tall.