Let us solve for x in each of the inequalities.
The first inequality.
[tex]5-2x<-3_{}[/tex]subtracting 5 from both sides gives
[tex]5-2x-5<-3_{}-5[/tex][tex]-2x<-8[/tex]finally, multiplying both sides by -2 reverse the direction of the inequality to give
[tex]-\frac{2x}{-2}>-\frac{8}{-2}[/tex][tex]\boxed{x>4}[/tex]which is our answer!
The second inequality
[tex]-3\mleft(-5+x\mright)>3[/tex]
Dividing both sides by -3 gives
[tex]\frac{3(-5+x)}{-3}<\frac{3}{-3}[/tex][tex]\rightarrow(-5+x)<-1[/tex]finally, adding -5 to both sides gives
[tex]-5+x+5<-1+5[/tex][tex]\begin{gathered} \rightarrow x<-1+5 \\ \boxed{x<4} \end{gathered}[/tex]which is our answer!
