Question

The length of a rectangle is 12 ft longer than twice the width. If the perimeter is 102 ft, find the length and width of the rectangle

Answer 1

Answer;

$\begin{gathered} \text{Length = 38 ft} \\ \text{Width = 13 ft} \end{gathered}$

Explanation;

Here, we want to get the length and width of the rectangle

Let the length of the rectangle be x ft

Let the width of the rectangle be w ft

From the question, the length is 12 ft more than twice the width

We have this as;

$l\text{ = 12 + 2w}$

Mathematically, the formula for the perimeter of a rectangle is;

$P\text{ = 2(l+w)}$

Now, substitute the value for l above and perimeter from the question

We have that as;

$\begin{gathered} 102\text{ = 2(12+2w+w)} \\ 51\text{ = 12 + 3w} \\ 3w\text{ = 51-12} \\ 3w\text{ = 39} \\ w\text{ = }\frac{39}{3} \\ w\text{ = 13 ft} \end{gathered}$

Recall;

$\begin{gathered} l\text{ = 12+2w} \\ l\text{ = 12+2(13)} \\ l\text{ = 12+26} \\ l\text{ = 38 ft} \end{gathered}$