[tex]f(x)=x^2+2x-3[/tex]
in order to find the zeros of the function
[tex]0=x^2+2x-3[/tex]
write the expression 2x as a difference
[tex]0=x^2+3x-x-3[/tex]
factor x
[tex]0=x\cdot(x+3)-x-3[/tex]
then rewrite -x-3
[tex]0=x\cdot(x+3)-(x+3)[/tex]
factor x+3
[tex]0=(x+3)\cdot(x-1)[/tex]
then the zeros of the function are
[tex]\begin{gathered} x+3=0 \\ x=-3 \\ x-1=0 \\ x=1 \\ \text{zeros are (-3,0) \& (1,0)} \end{gathered}[/tex]
