Question

16. A homeowner plans to install 2-ft. by 3-ft. tiles in his 18-ft by 32-ft basement. If thetiles cost $0.75 each, find the total cost of the tiles.

Answer 1

The Solution.

Given that the dimensions of a tile is 2 ft by 3 ft., we can find the area of a tile.

$\text{Area of Tile = 3}\times2=6ft^2$

Given that the dimensions of a Basement is 18 ft by 32 ft., we can find the area of the Basement as

$\text{Area of Basement = 18}\times32=576ft^2$

The number of tiles that will be installed in the basement is calculated as

$\text{Number of Tiles =}\frac{area\text{ of Basement}}{\text{area of a tile}}=\frac{576}{6}=96\text{ tiles}$

The total cost of the tiles will be

$\text{Total cost =0.75}\times96=\text{ \ 72}$

Thus, the correct answer is $72.00