Given that:
- The student selects a crayon at random.
- The probability of selecting an orange crayon is:
[tex]P(x=orange)=\frac{4}{3}[/tex]You need to remember that, by definition, the probability cannot be greater than 1 (or cannot be greater than 100%).
In this case, if you divide the numerator 4 by the denominator 3, you get:
[tex]4\div3\approx1.33[/tex]You can identify that the result is greater than 1.
Hence, the answer is: Option C.