The inverse of the function is;
[tex]\frac{\sqrt[3]{x\text{ }}\text{ +2}}{2}[/tex]Here, we want to find the inverse of the given function
We start by making x the subject of the formula
We have this as follows;
[tex]\begin{gathered} y=2(x-1)^3 \\ \sqrt[3]{y\text{ }}\text{ = 2(x-1)} \\ \sqrt[3]{y}\text{ = 2x - 2} \\ \sqrt[3]{y}\text{ + 2 = 2x} \\ \\ x\text{ = }\frac{\sqrt[3]{y}\text{ + 2}}{2} \end{gathered}[/tex]Now, we replace the y in the inverse equation with x
Thus, we have the inverse as;
[tex]\frac{\sqrt[3]{x\text{ }}\text{ +2}}{2}[/tex]