Respuesta :

Given

[tex]f(x)=3x^2-2[/tex][tex]h(x)\text{ = f(x+5) -2}[/tex]

Let us find f(x+5)

[tex]\begin{gathered} f(x+5)=3(x+5)^2-\text{ 2} \\ =\text{ 3(x+5)(x+5) - 2} \\ =3(x^2+5x+5x+25)-2 \\ =3(x^2+10x+25)\text{ - 2} \\ =3x^2+30x+75-2_{} \\ =3x^2+30x+73 \end{gathered}[/tex]

To find h(x)= f(x+5) - 2, we substitute for f(x+5)

Then, we have

[tex]\begin{gathered} h(x)=3x^2+30x+73\text{ - 2} \\ h(x)=3x^2+30x+71 \end{gathered}[/tex]

The answer to the function h(x) is 3x²+30x+71

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