Sketch the graph of the function. xy+12=0Choose the correct graph below.

Given:
[tex]xy+12=0[/tex]Required:
We need to graph the given equation.
Explanation:
Set x =1 and substitue in the given equation to find the point lie of the graph.
[tex](1)y+12=0[/tex][tex]y+12=0[/tex]Substract 12 from both sides of the equation.
[tex]y+12-12=0-12[/tex][tex]y=-12[/tex]We get the point (1.-12).
Set x = -1 and substitue in the given equation to find the point lie of the graph.
[tex](-1)y+12=0[/tex][tex]-y+12=0[/tex]Add y to both sides of the equation
[tex]-y+12+y=0+y[/tex][tex]12=y[/tex][tex]y=12[/tex]We get (-1, 12).
The points (1,-12) and (-1,12) are lies on the graph of the given equation.
Final answer:
The graph of the equation.