2 NaN3 -> 2Nat3 N2 Whatis the mole ratio of NaN3 to N22 How many grams of NaNa are needed to produce 144 grams of n2

GIVEN:
• mass of N2 =, 144 g
,• Molecular Mass N2 = ,28.02 g/mol
,• Molecular Mass NaN3 = ,65,0099 g/mol
The balanced equation of the chemical reaction is given by :
[tex]2NaN_3\Rightarrow\text{ 2Na+3N}_2[/tex]This means that 5.14 moles are produced from NaN3
by stoichiometry, we can see that :
• 2 Moles of NaN3 produces 3 moles N2
,• X moles of NaN3 produces 5.14 moles N2
X Moles NaN3 =( 5.14 moles N2 *2 moles NaN3 )/ 3 moles N2
=3.43 moles of NaN3
Then ; Mass of NaN3 will be calculated as :
[tex]\begin{gathered} Mass\text{ NaN}_3\text{= MolesNaN}_3\text{ * Molecular Mass NaN}_3\text{ } \\ \text{ = 3.43 moles * 65.0099g/mol} \\ \text{ =222.73 grams } \end{gathered}[/tex]