Question

A boat left a harbor and sailed 42 miles due north and then 35 miles due east. To the nearest mile, haw far away was the boat from the harbor?

Answer 1

In this case we can use the pythagorical theorem to find the distance so:

$x^2=42^2+35^2$

and we solve for x so:

$\begin{gathered} x=\sqrt{1764+1225} \\ x=\sqrt[]{2989} \\ x=54.67 \end{gathered}$

so he is at 54.67 miles