Question

Determine the maximum range a projectile would travel if its velocity at launch is 50 m/s at an angle of 40O above horizontal (assume the projectile lands at the same height it was launched).

Answer 1

The range of a projectile is given by:

$R=\frac{v^2_0\sin 2\theta}{g}$

where v0 is the initial velocity, theta is the angle and g is the acceleration of gravity. Plugging the values given we have that:

$\begin{gathered} R=\frac{(50)^2\sin (2\cdot40)}{9.8} \\ R=251.23 \end{gathered}$

Therefore the range is 251.23 meters