Question

what is the molarity of a solution tgat contain 0.050 mol c12h22o11 in 0.215 g water

Answer 1

Answer:

232.56M

Explanations:

The formula for calculating the molarity of the solution is expressed as:

$molarity=\frac{moles\text{ of solute}}{volume\text{ of solution}}$

Given the following parameters

moles of solute = 0.05moles

mass of solution (water) = 0.215g

Determine the volume of the solution

$\begin{gathered} volume=\frac{mass}{density} \\ volume\text{ of water}=\frac{0.215g}{1000gL^{-1}} \\ volume\text{ of water}=0.000215L \end{gathered}$

Determine the molarity of the solution

$\begin{gathered} molarity\text{ of the solution}=\frac{0.05}{0.000215} \\ molarity\text{ of the solution}=232.56M \end{gathered}$

Hence the molarity of a solution that contain 0.050 mol C12H22O11 in 0.215 g water is 232.56M