Use the following dot plot to determine which statements are true. Select all that apply.

Step 1
Given;
Step 2
We test all the options to know those that apply
[tex]\begin{gathered} 1)\text{ If 7 is deleted from the set, the median will stay the same } \\ The\text{ data written out is; 2,3,3,4,4,4,5,5,5,5,6,6,7} \end{gathered}[/tex]The median of the data is the middle number since the number of data is odd.
[tex]Median=5[/tex]when we remove 7, the data becomes
[tex]\text{ 2,3,3,4,4,4,5,5,5,5,6,6}[/tex]The median now will be;
[tex]\frac{4+5}{2}=\frac{9}{2}=4.5[/tex]Thus the first option is wrong. If 7 is removed from the set, the median changes.
[tex]\begin{gathered} 2)\text{ About half of the values are greater than the mean.} \\ mean=\frac{sum\text{ of data}}{number\text{ of data}}=\frac{2+3+3+4+4+4+5+5+5+5+6+6+7}{13} \end{gathered}[/tex][tex]mean=\frac{59}{13}[/tex]Half of the values will be;
[tex]\begin{gathered} The\text{ data appears evenly skewd} \\ Thus\text{ about half of te values is greater than the mean is correct} \end{gathered}[/tex][tex]\begin{gathered} If\text{ 2 is deleted from the data set, the median stays the same} \\ 2,\:3,\:3,\:4,\:4,\:4,\:5,\:5,\:5,\:5,\:6,\:6,\:7 \\ If\text{ we remove 2} \\ \:3,\:3,\:4,\:4,\:4,\:5,\:5,\:5,\:5,\:6,\:6,\:7 \end{gathered}[/tex]The median will be;
[tex]\begin{gathered} \frac{5+5}{2}=\frac{10}{2}=5 \\ The\text{ medain stays the same } \end{gathered}[/tex][tex]\begin{gathered} If\text{ one of the 5's is deleted from the set, the set becomes bimodal} \\ Bimodal\text{ means two modes} \\ If\text{ we remove one 5} \\ 2,\:3,\:3,\:4,\:4,\:4,\:\:5,\:5,\:5,\:6,\:6,\:7 \\ The\text{ modes are 4 and 5 since they occur highest. 3 times each} \\ Thus,\text{ yes, if one of the 5's is removed from the set, the set becomes bimodal} \end{gathered}[/tex]Answer;
About half of the values are greater than the mean.
If 2 is deleted from the set, the median will stay the same.
If one of the 5s is deleted from the set, the set will become bimodal.