Question

Two pools are being filled with water. To start, the first pool contains 1150 liters of water and the second pool contains 1300 liters of water. Water is being added to the first pool at rate of 30.5 liters per minute. Water is being added to the second pool at a rate of 24.25 liters per minute.

Answer 1

Given:

There are given that the first pool contains 1150 liters of water and the second pool contains 1300 liters of water.

Explanation:

Let P1 represent the first pool and P2 represent the second pool and t is represent the time in minutes.

Then,

From the first pool:

$1150+30.5t$

And,

From the second pool:

$1300+24.25t$

Now,

Equal both of the equations:

$\begin{gathered} 1,150+30.5t=1,300+24.25t \\ 1,150+30.5t-1,300-24.25t=0 \\ -150+6.25t=0 \\ -150=-6.25t \\ t=\frac{150}{6.25} \\ t=24 \end{gathered}$

And,

The volume of the water in both of pool is:

$\begin{gathered} 1,150+30.5t=1,150+30.5\left(24\right) \\ =1150+732 \\ =1882 \end{gathered}$

Final answer:

Hence, there are 24 minutes will the pools have the same amount of water and the volume of the water will be 1882 liters.