Question

Kate has two lengths of ribbon. the pink ribbon is 4 6/12 feet long, and the purple ribbon is 2 4/12 feet long. how much ribbon does kate have in all?

Answer 1

Data:
Kate has two lengths of ribbon
pink ribbon = $4 \frac{6}{12} \;feet$
purple ribbon = $2 \frac{4}{12} \;feet$

How much ribbon does kate have in all?
pink ribbon + purple ribbon

Solving:
$4\frac{6}{12} + 2\frac{4}{12} = \frac{12*4+6}{12} + \frac{12*2+4}{12} = \frac{48+6}{12} + \frac{24+4}{12} = \frac{54}{12} + \frac{28}{12} = \frac{82}{12} =$
$\frac{82}{12} \:simplify\: \frac{\div2}{\div2} = \boxed{\boxed{\frac{41}{6} \:or\:6 \frac{5}{6} }}\end{array}}\qquad\quad\checkmark$

Answer:
Kate has it all $6 \frac{5}{6}$ of ribbons

Answer 2

Answer:

$Data:

Kate has two lengths of ribbon

pink ribbon = 4 \frac{6}{12} \;feet4126feet 

purple ribbon = 2 \frac{4}{12} \;feet2124feet 

How much ribbon does kate have in all?

pink ribbon + purple ribbon

Solving:

4\frac{6}{12} + 2\frac{4}{12} = \frac{12*4+6}{12} + \frac{12*2+4}{12} = \frac{48+6}{12} + \frac{24+4}{12} = \frac{54}{12} + \frac{28}{12} = \frac{82}{12} =4126+2124=1212∗4+6+1212∗2+4=1248+6+1224+4=1254+1228=1282=$

$[tex]Data:

Kate has two lengths of ribbon

pink ribbon = 4 \frac{6}{12} \;feet4126feet 

purple ribbon = 2 \frac{4}{12} \;feet2124feet 

How much ribbon does kate have in all?

pink ribbon + purple ribbon

Solving:

4\frac{6}{12} + 2\frac{4}{12} = \frac{12*4+6}{12} + \frac{12*2+4}{12} = \frac{48+6}{12} + \frac{24+4}{12} = \frac{54}{12} + \frac{28}{12} = \frac{82}{12} =4126+2124=1212∗4+6+1212∗2+4=1248+6+1224+4=1254+1228=1282=$

Kate has it all 6 \frac{5}{6}665 of ribbons[/tex]