Question

Triangle ABC shown below has m C = 146°, a = 10, and b = 11. Find the area of the triangle. =

Answer 1

We have two sides a and b and an angle C in this case we can use the next formula to find the area of the given triangle

$A=\frac{1}{2}ab\sin C$

a=10

b=11

m

we substitute the values

$A=\frac{1}{2}(10)(11)\sin (146)=30.76$

The area of the triangle is 30.76

ANSWER

Area=30.76