Question

37. Six test scores for Jonathan's history class arelisted. Find the mean and median. Round tothe nearest tenth if necessary. Did the mean ormedian give a better overall score forJonathan's performance?92%, 98%, 43%, 98%, 97%, 85%

Answer 1

$\begin{gathered} \operatorname{mean}=\frac{92+98+43+98+97+85}{6} \\ \operatorname{mean}=\frac{513}{6} \\ \operatorname{mean}=85.5 \\ \text{For median} \\ 43,85,92,97,98,98 \\ \operatorname{median}=\frac{92+97}{2} \\ \operatorname{median}=\frac{189}{2} \\ \operatorname{median}=94.5 \end{gathered}$