To answer the question we need to find the equation of the line, this is given by:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Using the points given we have:
[tex]\begin{gathered} y-62=\frac{63-62}{93-90}(x-90) \\ y-62=\frac{1}{3}(x-90) \\ y=\frac{1}{3}x-30+62 \\ y=\frac{1}{3}x+32 \end{gathered}[/tex]
Then we have to remeber that x represents the number of chirps and y the temperature. If we have 96 chirps (that is x=96), then:
[tex]\begin{gathered} y=\frac{1}{3}\cdot96+32 \\ y=32+32 \\ y=64 \end{gathered}[/tex]
Therefore the temperature is likely to be 64° F.