We are given the following
[tex]v=60\sin \mleft(\theta\mright),\theta=610^{\circ\: }[/tex]we can also replace
[tex]\theta=610-360=250[/tex]then
[tex]\begin{gathered} v=60\sin \mleft(250^{\circ\: }\mright)=60\cdot(-0.93969) \\ v=-56.38155 \end{gathered}[/tex]Therefore, the answer is the last one