Question

solve each equation 3 + c = 15 7=m+11c-24=1016=g-52n=84-5r=20$\frac{c}{4} = 16$$a \times \frac{2}{3 } = 12$

Answer 1

3 + c = 15

subtract 3 from both-side of the equation

3 - 3 + c = 15 -3

c= 12

7 = m+ 11

subtract 11 from both-side of the equation

7 - 11 = m+11 - 11

-4 = m

m=-4

c-24=10

add 24 to both-side of the equation

c - 24+ 24= 10 + 24

c= 34

16 = g- 5

add 5 to both-side of the equation

16+5 = g - 5 + 5

21 = g

g= 21

2n = 84

divide both-side of the equation by 2

2n/2 = 84/2

n =42

-5r = 20

dvide both-side of the equation by -5

-5r/-5 = 20/-5

r = -4

c/4 = 16

multiply both-side of the equation by 4

c = 16(4)

c= 64

$\frac{2}{3}a=\text{ 12}$

multiply both-side of the equation by 3/2

$a=12\times\frac{3}{2}$

$a=\frac{36}{2}$

a= 18