Find the equation of the line shown in the graph. Write the equation in slope-intercept form. Y=

Explanation
the slope-intercept form of a line is
[tex]\begin{gathered} y=mx+b \\ \text{where m is the slope and b is the y-intercept} \end{gathered}[/tex]Step 1
find the slope of the line:
the slope of a line is given by:
[tex]\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ \text{and} \\ P2(x_2,y_2) \\ \text{are 2 points from the line} \end{gathered}[/tex]then
pick 2 points from the line:
let
P1(0,-1)
P2(2,0)
now, replace and get the slope
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{0-(-1)}{2-0}=\frac{1}{2} \end{gathered}[/tex]so, the slope (m) is 1/2
Step 2
now, we need the y-intercept(b), if we have the graph, the simplest way to find the y-intercept is by watching the point where the line crosses the y-axis, in this case
[tex]y-\text{intercept}=-1[/tex]so, we have
slope=m=1/2
y-intercept=-1
replace
[tex]y=mx+b\rightarrow y=\frac{1}{2}x-1[/tex]so, the answer is
[tex]y=\frac{1}{2}x-1[/tex]I hope this helps you