Respuesta :

[tex]\int\frac{1}{x^4}dx[/tex]

We can find the integral using the following properties:

[tex]\begin{gathered} a^{-n}=\frac{1}{a^n} \\ \int x^ndx=\frac{x^{n+1}}{n+1} \end{gathered}[/tex]

So:

[tex]\begin{gathered} \int\frac{1}{x^4}dx=\int x^{-4}dx=\frac{x^{-4+1}}{-4+1}=\frac{x^{-3}}{-3}=-\frac{1}{3x^3} \\ Answer: \\ -\frac{1}{3x^3} \end{gathered}[/tex]

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