Question

In the standard (x, y) coordinate plane below, the points (0,0), (10,0), (13,6), and (3,6) are the vertices of a parallelogram. What is the area, in square coordinate units, of the parallelogram?

Answer 1

Solution

For this case we can do the following:

We can find the individual areas and we got:

$A_1=\frac{3\cdot6}{2}=9$$A_2=7\cdot6=42$$A_3=\frac{3\cdot6}{2}=9$

The total area is given by:

At = 42+9+9 = 60