First box options are -22-1/21/2second box options are -55-33Third boxes options are -2-112fourth options -2-121

DEFINITIONS AND FORMULAS
The equation of a straight line can be written in the slope-intercept form to be:
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
The formula to calculate the slope is given to be:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]SOLUTION
Table 1: Two points can be picked from the table as shown below
[tex]\begin{gathered} (x_1,y_1)=(-5,10) \\ (x_2,y_2)=(0,0) \end{gathered}[/tex]Therefore, the slope is calculated to be:
[tex]m=\frac{0-10}{0-(-5)}=-\frac{10}{5}=-2[/tex]The y-intercept is the value on the y-axis when the x-axis is 0. Therefore:
[tex]\begin{gathered} At \\ x=0,y=0 \\ \therefore \\ b=0 \end{gathered}[/tex]Therefore, the equation of the first table is:
[tex]y=-2x[/tex]Table 2: Two points can be picked from the table as shown below
[tex]\begin{gathered} (x_1,y_1)=(-8,-11) \\ (x_2,y_2)=(1,-2) \end{gathered}[/tex]Therefore, the slope is calculated to be:
[tex]m=\frac{-2-(-11)}{1-(-8)}=\frac{-2+11}{1+8}=\frac{11}{11}=1[/tex]Therefore, the equation of the line is:
[tex]y=x+b[/tex]To find the value of b, we need to substitute one of the ordered pairs in the table into the equation and solve for b:
[tex]\begin{gathered} \text{Using} \\ (x,y)=(1,-2) \\ \therefore \\ -2=1+b \\ b=-2-1 \\ b=-3 \end{gathered}[/tex]Therefore, the equation of the second table is:
[tex]y=x-3[/tex]To get the solution to the system of equations, we can plot the graphs of the equations. This is shown below:
The solution to the system is the point where both graphs intersect.
Therefore, the solution to the system is:
[tex](x,y)=(1,-2)[/tex]ANSWERS
The equation of the first system is:
[tex]y=-2x[/tex]The equation of the second system is:
[tex]y=x-3[/tex]The solution to the system is:
[tex](1,-2)[/tex]