Question

In 2014, the CDC estimated that the mean height for adult women in the U.S. was 64 inches with a standard deviation of4 inches. Suppose X, height in inches of adult women, follows a normal distribution. Let x = 68, the height of a womanwho is 5'8" tall. Find and interpret the Z-score of the standardized normal random variable.

Answer 1

$\begin{gathered} Z-\text{score = }\frac{X-X^i}{\partial} \\ \text{Where X}^i=\operatorname{mean}\text{ and }\partial=\text{ standard deviation} \\ \text{From the information provided, } \\ X=68,X^i=64,\text{ }\partial=4 \\ Z-\text{score = }\frac{68-64}{4}\text{ = }\frac{4}{4}\text{ = 1} \end{gathered}$

From the result, the correct answer is option A, that is the first option