Write the complete ground-state electron configuration of Mn⁴⁺.To this I wrote1S2 2S2 2P6 3S2 3P6 4S2 3D1My homework says I have it wrong, but I don't know why, please help.

Respuesta :

The electronic configuration tells us how the electrons are configured within the atom. To write the electronic configuration of Manganese (Mn) we first check its atomic number in the periodic table, this will tell us the number of protons that the element has. The number of protons in Mn is 25.

In a neutral atom, the number of electrons will be equal to the number of protons, but in this case, we have an ion with a positive charge +4.

But since it tells us to write down its ground state configuration you can refer to writing down the Mn atom configuration. Therefore we will take into account the 25 electrons of Mn.

Now, to fix the electrons and the way in which the electrons are filled, we can be guided by the Aufbau principle. The following figure shows a scheme of how the electrons are filled:

Source: https://commons.wikimedia.org/wiki/File:Atomic_orbital_diagonal_rule.svg

Now we are writing the configuration following the order of the arrows until completing 25 electrons.

We must remember that we have different kinds of orbitals and each orbital has the capacity to hold a maximum number of electrons. The s orbital holds 2 electrons, the p orbital holds 6.

Therefore the configuration will be:

[tex]1s^22s^22p^63s^23p^64s^23d^5[/tex]

The coefficient of each orbital represents the energy level, that is to say, that here we have 4 energy levels.

The superscripts represent the number of electrons, the sum of them must be equal to 25 in this case.

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