Question

There is a net passage of 3.7 1018 electrons by a point in a wire conductor in 0.21 s. What is the current in the wire? answer in:______A

Answer 1

Answer:

2.82 A

Explanation:

The current of the wire can be calculated as:

$I=\frac{Q}{t}$

Where Q is the charge and t is the time.

The charge of an electron is 1.6 x 10^(-19) C, so the charge of 3.7 x 10^(18) electron is equal to

$3.7\times10^{18}\text{ electrons}\times1.6\times10^{-19}\text{ C/electron}=0.592\text{ C}$

Then, replacing Q = 0.592 C, and t = 0.21 s, we get:

$I=\frac{0.592\text{ C}}{0.21\text{ s}}=2.82\text{ A}$

Therefore, the answer is 2.82 A