Answer
19.93 mol
Explanation
Given:
The number of particles of CN = 1.2 x 10²⁵
What to find:
The number of moles of CN present in 1.2 x 10²⁵ particles of CN.
Step-by-step solution:
According to Avogadro, 1 mole of CN has 6.022 x 10²³ particles.
Therefore, the number of moles of CN present in 1.2 x 10²⁵ particles of CN will be:
[tex]\frac{1\text{ }mol\times1.2\times10^{25}\text{ }particles}{6.022\times10^{23}\text{ }particles}=19.93\text{ }mol[/tex]The number of moles of CN present in 1.2 x 10²⁵ particles of CN = 19.93 mol.
