Question

0.025 kg bullet is shot out of a 0.45 m rifle barrel. The force on the bullet is 3600 N. What is the muzzle speed (the speed that the bullet leaves the gun barrel) of the bullet?

Answer 1

Answer:

The muzzle speed of the bullet = 360 m/s

Explanations:

Mass of the bullet, m = 0.025 kg

Length of the rifle, d= 0.45 m

Force on the bullet, F = 3600 N

Workdone on the bullet (W) = Force on the bullet (F) x Length of the rifle(d)

W = Fd

W = 3600 x 0.45

W = 1620 Joules

Kinetic energy of the bullet, KE = 0.5mv²

where v is the speed that the bullet leaves the gun barrel

KE = 0.5 x 0.025 x v²

KE = 0.0125v²

Workdone on the bullet = Kinetic Energy on the bullet

W = KE

1620 = 0.0125v²

v² = 1620/0.0125

v² = 129600

v = 360 m/s

The muzzle speed of the bullet = 360 m/s