we have the following:
[tex]2|x-1|-4>2[/tex]solving:
[tex]\begin{gathered} 2|x-1|-4+4>2+4 \\ \frac{2}{2}|x-1|>\frac{6}{2} \\ |x-1|>3 \\ x-1<-3\rightarrow x<-2 \\ x-1>3\rightarrow x>4 \end{gathered}[/tex]The answer is:
[tex]\begin{gathered} x<-2,(-\infty,-2) \\ x>4,(4,\infty) \end{gathered}[/tex]