We need to add the two fractions.
The problem is:
[tex]4\frac{2}{5}+5\frac{3}{10}[/tex]We first convert the mixed numbers into improper fraction using the rule shown below:
[tex]a\frac{b}{c}=\frac{(a\times c)+b}{c}[/tex]Thus, the problem becomes:
[tex]\begin{gathered} 4\frac{2}{5}+5\frac{3}{10} \\ =\frac{(4\times5)+2}{5}+\frac{(5\times10)+3}{10} \\ =\frac{20+2}{5}+\frac{50+3}{10} \\ =\frac{22}{5}+\frac{53}{10} \end{gathered}[/tex]Now, we take the common denominator, 10, and add them. The steps are shown below:
[tex]\begin{gathered} \frac{22}{5}+\frac{53}{10} \\ =\frac{22}{5}\times\frac{2}{2}+\frac{53}{10} \\ =\frac{22\times2}{5\times2}+\frac{53}{10} \\ =\frac{44}{10}+\frac{53}{10} \\ =\frac{44+53}{10} \\ =\frac{97}{10} \\ \end{gathered}[/tex]We can against convert it back to mixed number :
[tex]\begin{gathered} \frac{97}{10} \\ =9\frac{7}{10} \end{gathered}[/tex]The correct answer is:
[tex]9\frac{7}{10}\text{ pounds}[/tex]