Given:
The power of each hair dryer is,
[tex]P=1250\text{ W}[/tex]The potential across the circuit is,
[tex]V=120\text{ V}[/tex]The fuse has current
[tex]i=20\text{ A}[/tex]To find:
Is it possible to use that fuse or not
Explanation:
The power for two heaters is,
[tex]\begin{gathered} P^{\prime}=2P \\ =2\times1250 \\ =2500\text{ W} \end{gathered}[/tex]The current for this power is,
[tex]\begin{gathered} I=\frac{P^{\prime}}{V} \\ =\frac{2500}{120} \\ =20.8\text{ A} \end{gathered}[/tex]Here, we see the current for the dryers is greater than the fuse's current.
Hence, it is not possible to use the given fuse.