Question

For the following reaction, if 16.4 g of Cl2, is reacted with excess Al, what is the theoretical yield of AlCl3 for this reaction? Round your answer to the nearest gram.2 Al + 3 Cl2 → 2 AlCl3Select one:a. 32b. 21c. 16d. 63

Answer 1

1) Balance the chemical equation.

$2Al+3Cl_3\rightarrow2AlCl_3$

2) List the known and unknown quantities.

Reactant: Cl2

Mass: 16.4 g

Product: AlCl3

Mass: unknown (g).

3) Convert the mass of Cl2 to moles of Cl2.

The molar mass of Cl2 is 70.9060 g/mol.

$mol\text{ }Cl_2=16.4\text{ }g\text{ }Cl_2*\frac{1\text{ }mol\text{ }Cl_2}{70.9060\text{ }g\text{ }Cl_2}=0.23129\text{ }mol\text{ }Cl_2$

4) Convert moles of Cl2 to moles of AlCl3.

The molar ratio between Cl2 and AlCl3 is 2 mol Cl2: 2 mol AlCl2.

$mol\text{ }AlCl_2=0.23129\text{ }mol\text{ }Cl_2*\frac{2\text{ }mol\text{ }AlCl_2}{2\text{ }mol\text{ }Cl_2}=0.23129\text{ }mol\text{ }AlCl_3$

5) Convert moles of AlCl3 to mass of AlCl3.

The molar mass of AlCl3 is 133.3405 g/mol.

$g\text{ }AlCl_3=0.23129\text{ }mol\text{ }AlCl_3*\frac{133.3405\text{ }g\text{ }AlCl_3}{1\text{ }mol\text{ }AlCl_3}=30.840324\text{ }g\text{ }AlCl_3$

The theoretical yield rounded to the nearest gram is 31 g AlCl3.

Option A: 32