Solution
[tex]a_{12}=element\text{ }in\text{ }the\text{ }first\text{ }row\text{ }and\text{ }second\text{ }column\text{ }after\text{ }multiplication[/tex][tex]\begin{bmatrix}{24} & {32} \\ {60} & {10}\end{bmatrix}\begin{bmatrix}{1} & {2} & {0} \\ {0} & {3} & {1} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{} & {} & {} \\ {24\times1+32\times0} & {24\times2+32\times3} & {24\times0+32\times1} \\ {\placeholder{⬚}} & {\placeholder{⬚}} & {\placeholder{⬚}}\end{bmatrix}[/tex]
Along the first row , we have the elements
(24 144 32)
The element on the first row ; second column is 144
