Given the equation
[tex]3x-2(6-x)=7x+2(5+x)-6[/tex]
You need to solve it for x.
The fist step is to solve the terms in parenthesis, for this you have to apply the distributive propperties of multiplication.
a(b+c)= ab+ac
[tex]\begin{gathered} 3x-(2\cdot6)-(2\cdot-x)=7x+(2\cdot5)+(2\cdot x)-6 \\ 3x-12+2x=7x+10+2x-6 \end{gathered}[/tex]
Next order all alike terms together
[tex]\begin{gathered} 3x+2x-12=7x+2x+10-6 \\ 5x-12=9x+4 \end{gathered}[/tex]
Pass the x related terms to one side of the equation and all numbers to the other one
[tex]\begin{gathered} 5x-9x=4+12 \\ -4x=16 \\ x=-4 \end{gathered}[/tex]
