What is the slope of the line created by this equation?Round your answer out to two decimal places.3x+5y=7

The given equation is
[tex]3x+5y=7[/tex]Consider the slope-intercept form.
[tex]y=mx+b[/tex]Rewriting the given equation in the slope-intercept form.
[tex]3x+5y=7[/tex]Subtracting 3x from both sides, we get
[tex]3x+5y-3x=7-3x[/tex]Dividing both sides by 5, we get
[tex]\frac{5y}{5}=\frac{7-3x}{5}[/tex][tex]y=-\frac{3}{5}x+\frac{7}{5}[/tex][tex]y=-0.6x+1.4[/tex]Compared to the slope-intercept form, we get m=-0.6 and b=1.4.
Hence the slope m= -0.60.