This in an absolute value equation so might need to use the property:
[tex]\lvert x\rvert=a\Rightarrow x=\pm a[/tex]With this in mind we can solve it:
[tex]\begin{gathered} 7+3\lvert-2x-5\rvert=-8 \\ 3\lvert-2x-5\rvert=-8-7 \\ 3\lvert-2x-5\rvert=-15 \\ \lvert-2x-5\rvert=-\frac{15}{3} \\ \lvert-2x-5\rvert=-5 \end{gathered}[/tex]Now, since the absolute value is always positive this means that this equation has no solution.
