Question

What is the equation of the given circle? O A. (x-3) + (y + 2)2 = 1 O B. (x+3)+ (v - 2)2 = 2 O c. (x - 3)2 + (y + 2)2 = 2 (x+3)2+(y - 2) = 1 2 D.

Answer 1

We want to get the equation of the circle.

The equation of a circle wih radius (h,k) and radius r is given as;

$(x-h)^2+(y-k)^2=r^2$

The coordinates of the centre here is ( -3, 2) and the radius is 1 unit.

Therefore, the equation of the circle is;

$(x+3)^2+(y-2)^2=1$

Option D