Does anyone know how to do this? This looks familiar to me but I don’t know what to do.

Let us set x for the missing score.
Now, if he wants to keep an average of 86 or greater, we need to use the next inequality:
[tex]\frac{68+84+x}{3}≥86[/tex]Then, we need to solve for x:
[tex]\frac{152+x}{3}≥86[/tex]Multiply both sides by 3:
[tex]\begin{gathered} (3)\frac{152+x}{3}≥(3)(86) \\ 152+x≥258 \end{gathered}[/tex]Subtract both sides by 152:
[tex]152-152+x≥258-152[/tex]Simplify:
[tex]x≥104[/tex]In this case, the score is 104 is greater than the possible number of points.
Hence, enter DNE